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A plot of $\ln K$ against $\frac{1}{T}$ (abscissa) is expected to be a straight line with intercept on ordinate axis equal to
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Verified Answer
The correct answer is:
$\frac{\Delta S^{\circ}}{R}$
$\begin{array}{l}
R T \ln K=-\Delta G^{\circ}=T \Delta S^{\circ}-\Delta H^{\circ} \\
\ln K=\frac{\Delta S^{\circ}}{R}-\frac{\Delta H^{\circ}}{R T}
\end{array}$
Thus, a plot of $\ln K$ versus $1 / T$ (abscissa) will be straight line with slope equal to $\frac{-\Delta H^{\circ}}{R}$ and intercept $\frac{\Delta S^{\circ}}{R}$
R T \ln K=-\Delta G^{\circ}=T \Delta S^{\circ}-\Delta H^{\circ} \\
\ln K=\frac{\Delta S^{\circ}}{R}-\frac{\Delta H^{\circ}}{R T}
\end{array}$
Thus, a plot of $\ln K$ versus $1 / T$ (abscissa) will be straight line with slope equal to $\frac{-\Delta H^{\circ}}{R}$ and intercept $\frac{\Delta S^{\circ}}{R}$
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