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A plot of $\log (x / m)$ versus $\log p$ for the adsorption of a gas on a solid gives a straight line with slope equal to:
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The correct answer is:
$1 / n$
The empirical relation $\frac{x}{m}=k p^{\frac{1}{n}}$, is known as the Freundlich adsorption isotherm. Taking the logarithm on both sides, $\log \frac{x}{m}=\log k=\frac{1}{n} \log p$
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