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A p-n junction diode is reverse biased with a voltage of $8 \mathrm{~V}$. If the resistance of the diode is $4 \times 10^7 \Omega$, then the reverse saturation current is
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Verified Answer
The correct answer is:
$0.2 \mu \mathrm{A}$
Saturation current
$$
\begin{aligned}
& \mathrm{I}=\frac{\mathrm{v}(\text { reverse biased voltage })}{\text { diode resistance }} \\
& =\frac{8}{4 \times 10^7}=0.2 \mu \mathrm{A}
\end{aligned}
$$
$$
\begin{aligned}
& \mathrm{I}=\frac{\mathrm{v}(\text { reverse biased voltage })}{\text { diode resistance }} \\
& =\frac{8}{4 \times 10^7}=0.2 \mu \mathrm{A}
\end{aligned}
$$
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