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A p-n photodiode is fabricated from a semiconductor with a band gap of $2.5 \mathrm{eV}$. It can detect a signal of wavelength :
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2750 Upvotes
Verified Answer
The correct answer is:
$496 Å$
$$
\text { } \begin{aligned}
\lambda_{\max } & =\frac{\mathrm{hc}}{\mathrm{eV}} \\
& =\frac{1242 \mathrm{eV} Å}{2.5 \mathrm{eV}}=4960 Å
\end{aligned}
$$
\text { } \begin{aligned}
\lambda_{\max } & =\frac{\mathrm{hc}}{\mathrm{eV}} \\
& =\frac{1242 \mathrm{eV} Å}{2.5 \mathrm{eV}}=4960 Å
\end{aligned}
$$
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