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Question: Answered & Verified by Expert
A point charge causes an electric flux of \( -200 \mathrm{~N} \mathrm{~m}^{2} \mathrm{C}^{-1} \) to pass through spherical Gaussian surface of \( 10 \mathrm{~cm} \) radius
centered on the charge. If the radius of the Gaussian surface is doubled, the total electric flux passing through the surface is
PhysicsElectrostaticsJEE Main
Options:
  • A \( -200 \mathrm{Nm}^{2} \mathrm{C}^{-1} \)
  • B \( -100 \mathrm{Nm}^{-2} \mathrm{C}^{-1} \)
  • C \( +200 \mathrm{Nm}^{2} \mathrm{C}^{-1} \)
  • D \( -50 \mathrm{Nm}^{2} \mathrm{C}^{-1} \)
Solution:
1313 Upvotes Verified Answer
The correct answer is: \( -200 \mathrm{Nm}^{2} \mathrm{C}^{-1} \)

According to Gauss's theorem, electric flux through a closed surface is given by, =qε0,

where, q is charge enclosed, ε0 is constant.

Here even if the radius is doubled, the charge enclosed is the same, so the flux through the surface is also the same.

Hence, flux is -200 Nm2 C-1.

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