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A point object is placed $20 \mathrm{~cm}$ left of a convex lens of focal length $\mathrm{f}=5 \mathrm{~cm}$ (see the figure). The lens is made to oscillate with small amplitude A along the horizontal axis. The image of the object will also oscillate along the axis with.
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amplitude $\mathrm{A} / 9$, out of phase with the oscillations of the lens.
$$
\begin{array}{l}
\frac{1}{v}+\frac{1}{20}=\frac{1}{5} \\
v=\frac{20}{3} \mathrm{~cm}
\end{array}
$$
$$
\Delta x_{i}=\frac{+v^{2}}{u^{2}} \Delta x_{o}
$$
$\Delta x_{i}=\frac{A}{9}$ out of phase with lens Hence (A) is correct
\begin{array}{l}
\frac{1}{v}+\frac{1}{20}=\frac{1}{5} \\
v=\frac{20}{3} \mathrm{~cm}
\end{array}
$$
$$
\Delta x_{i}=\frac{+v^{2}}{u^{2}} \Delta x_{o}
$$
$\Delta x_{i}=\frac{A}{9}$ out of phase with lens Hence (A) is correct
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