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Question: Answered & Verified by Expert
A point P consider at the contact point of a wheel on the ground which roll on the ground without slipping, then the value of the displacement of point $\mathrm{P}$ when wheel completes half of the rotation (if radius of wheel is $1 \mathrm{~m}$ )is:
PhysicsRotational MotionJEE Main
Options:
  • A $2 \mathrm{~m}$
  • B $\sqrt{\pi^2+4} \mathrm{~m}$
  • C $\pi \mathrm{m}$
  • D $\sqrt{\pi^2+2} \mathrm{~m}$
Solution:
2858 Upvotes Verified Answer
The correct answer is: $\sqrt{\pi^2+4} \mathrm{~m}$

Displacement $P Q$
$\begin{aligned}
& =\sqrt{(P M)^2+(Q M)^2} \\
& =\sqrt{(\pi R)^2+(2 R)^2} \\
& =\sqrt{\pi^2+4}\{\because R=1 \mathrm{~m}\}
\end{aligned}$

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