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Question: Answered & Verified by Expert
A point P moves in a counter-clockwise direction on a circular path as shown in the figure. The movement of P is such that it sweeps out a length s=t3+5 where s is in metre and t is in seconds. The radius of the path is 27 m. The acceleration of P when t=3 s is ____ m/s2. Take13=3.6
PhysicsLaws of MotionJEE Main
Solution:
1496 Upvotes Verified Answer
The correct answer is: 32.40
As s=t3+5
dsdt=3t2=v
at=dvdt=6t
a=ac2+at2
At t=3s
a=v2R2+at2=9t4R2+6t2
=272+324=1053=913
a=32.4 m/s2

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