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A point source emits sound equally in all directions in a non-absorbing medium. Two points $\mathrm{P}$ and $\mathrm{Q}$ are at distances of 2 $\mathrm{m}$ and $3 \mathrm{~m}$ respectively from the source. The ratio of the intensities of the wave at $P$ and $Q$ is:
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The correct answer is:
$9: 4$
$$
\begin{aligned}
& d_1=2 \mathrm{~m}_1 d_2=3 \mathrm{~m} \\
& \text { Intensity } \propto \frac{1}{(\text { distance })^2} \\
& I_1 \propto \frac{I}{2^2} \text { and } I_2 \propto \frac{1}{3^2} \\
& \therefore \quad \frac{I_1}{I_2}=\frac{9}{4}
\end{aligned}
$$
\begin{aligned}
& d_1=2 \mathrm{~m}_1 d_2=3 \mathrm{~m} \\
& \text { Intensity } \propto \frac{1}{(\text { distance })^2} \\
& I_1 \propto \frac{I}{2^2} \text { and } I_2 \propto \frac{1}{3^2} \\
& \therefore \quad \frac{I_1}{I_2}=\frac{9}{4}
\end{aligned}
$$
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