A population is in Hardy-Weinberg equilibrium for a gene with only 2 alleles. If the gene frequency of an allele A is 0.7, the genotypic frequency of homozygous recessive individuals will be:

Question

A population is in Hardy-Weinberg equilibrium for a gene with only 2 alleles. If the gene frequency of an allele A is 0.7, the genotypic frequency of homozygous recessive individuals will be:, 0.49, 0.42, 0.09, 0.9

MARKS App · Accepted Answer

Gene frequency of allele A = 0.7 . That means ‘ p ’ = 0.7 . According to Hardy-Weinberg equilibrium p + q = 1 . Thus q = 1 - 0.7 = 0.3 Hence, gene frequency of homozygous recessive q 2 = 0.3 × 0.3 = 0.09

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