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A potential difference of $300 \mathrm{volts}$ is applied to a combination of $2.0 \mu \mathrm{F}$ and $8.0 \mu \mathrm{F}$ capacitors connected in series. The charge on the $2.0 \mu \mathrm{F}$ capacitor is
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The correct answer is:
$4.8 \times 10^{-4} \mathrm{C}$
In series combination charge $Q$ is same. So charge on $2 \mu \mathrm{F}$ capacitor is
$Q=C_{\text {eq }} V=\left(\frac{2 \times 8}{2+8}\right) \times 300 \times 10^{-6}=4.8 \times 10^{-4} \mathrm{C}$
$Q=C_{\text {eq }} V=\left(\frac{2 \times 8}{2+8}\right) \times 300 \times 10^{-6}=4.8 \times 10^{-4} \mathrm{C}$
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