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Question: Answered & Verified by Expert
A potentiometer wire AB having length L and resistance 12r is joined to a cell D of emf ε and internal resistance r. A cell C having EMF ε/2 and internal resistance 3r is connected. The length AJ, at which the galvanometer, as shown in the figure, shows no deflection is

PhysicsCurrent ElectricityNEET
Options:
  • A 512L
  • B 1124L
  • C 1112L
  • D 1324L
Solution:
2991 Upvotes Verified Answer
The correct answer is: 1324L
Potential difference across AJ=Ix,

=ε13r·12rL·x

For no current in galvanometer,

ε2= potential difference across AJ

ε2=12ε13Lx

x=13L24

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