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A power transmission line feeds input power at $2300 \mathrm{~V}$ to a step down transformer with its primary windings having $\mathbf{4 0 0 0}$ turns. What should be the number of turns in the secondary in order to get output power at $230 \mathrm{~V}$ ?
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Here $E_p=2300 \mathrm{~V}, N_p=400$ turns, $\mathrm{E}_{\mathrm{s}}=230 \mathrm{~V}, \mathrm{~N}_{\mathrm{s}}=$ ?
We know in a transformer, $\frac{E_S}{E_p}=\frac{N_S}{N_p}$
$$
N_s=\frac{E_s N_p}{E_p}=\frac{230 \times 4000}{2300}=400 \mathrm{turns}
$$
We know in a transformer, $\frac{E_S}{E_p}=\frac{N_S}{N_p}$
$$
N_s=\frac{E_s N_p}{E_p}=\frac{230 \times 4000}{2300}=400 \mathrm{turns}
$$
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