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A prism of crown glass with refracting angle of $5^{\circ}$ and mean refractive index $=1.51$ is combined with a flint glass prism of refractive index $=1.65$ to produce no deviation. Find the angle of flint glass.
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The correct answer is:
$3.92^{\circ}$
Let $A^{\prime}$ be the angle of flint glass prism.
Here, $\mathrm{A}=5^{\circ}$ and $\mu=1.51$ for crown glass prism. Deviation produced by flint glass,
$\delta^{\prime}=(\mu-1) \mathrm{A}=(1.51-1) \times 5=2.55^{\circ}$
For no deviation, $\delta^{\prime}=\delta$
Or $0.65 \mathrm{~A}^{\prime}=2.55$
$\mathrm{A}^{\prime}=\frac{2.55}{0.65}=3.92^{\circ}$
Here, $\mathrm{A}=5^{\circ}$ and $\mu=1.51$ for crown glass prism. Deviation produced by flint glass,
$\delta^{\prime}=(\mu-1) \mathrm{A}=(1.51-1) \times 5=2.55^{\circ}$
For no deviation, $\delta^{\prime}=\delta$
Or $0.65 \mathrm{~A}^{\prime}=2.55$
$\mathrm{A}^{\prime}=\frac{2.55}{0.65}=3.92^{\circ}$
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