Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A progressive wave is represented by y=12sin(5t-4x) cm. On this wave, how far away are the two points having a phase difference of 90°?
PhysicsWaves and SoundNEET
Options:
  • A π2 cm
  • B π 4 cm
  • C π8  cm
  • D π16 cm
Solution:
1094 Upvotes Verified Answer
The correct answer is: π8  cm
y=12 sin (5t-4x)

Comparing in y=Asinwt-kx

We have A=12, w=5 and k=4

wt-kx= phase difference =π2


| 5t4x |= π 2

When t=0, 4x=π2

x=π8 cm

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.