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A progressive wave moving along $x$ -axis is represented by $y=A \sin \left[\frac{2 \pi}{\lambda}(v t-x)\right]$ The
wavelength $(\lambda)$ at which the maximum particle velocity is 3 times the wave velocity is
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wavelength $(\lambda)$ at which the maximum particle velocity is 3 times the wave velocity is
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Verified Answer
The correct answer is:
$(2 / 3) \pi A$
$y=A \sin \left[\frac{2 \pi}{\lambda}(v t-x)\right]$
$v=\frac{2 \pi}{\lambda} V A$
$$
\begin{aligned}
\left(v_{p}\right)_{\max } &=3 v \\
\lambda &=\frac{2 \pi}{3} A
\end{aligned}
$$
$v=\frac{2 \pi}{\lambda} V A$
$$
\begin{aligned}
\left(v_{p}\right)_{\max } &=3 v \\
\lambda &=\frac{2 \pi}{3} A
\end{aligned}
$$
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