A projectile fired at 30 ° to the ground is observed to be at same height at time 3 s and 5 s after projection, during its flight. The speed of projection of the projectile is m s - 1 . (Given g = 10 m s - 2 )

Question

A projectile fired at 30 ° to the ground is observed to be at same height at time 3 s and 5 s after projection, during its flight. The speed of projection of the projectile is m s - 1 . (Given g = 10 m s - 2 ),

MARKS App · Accepted Answer

The time taken to reach maximum height is T ' = u sin θ g . The total time of flight is T = ( 3 + 5 ) s = 8 s . Hence, T ' = T 2 = 3 + 5 2 = u sin θ g ⇒ 4 = ( u ) × 1 2 10 ⇒ u = 80 m s - 1

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