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Question: Answered & Verified by Expert
A projectile is fired with the velocity v0= 2 m s-1 at an angle 60o with horizontal. At top of its trajectory, it explodes into three fragments of equal mass. The first fragment retraces the path, second moves vertically upward with speed 3v02. The speed of the third fragment (in m s-1) is
 
PhysicsCenter of Mass Momentum and CollisionJEE Main
Solution:
2192 Upvotes Verified Answer
The correct answer is: 5
Picture 73
Let velocity of third fragment be V
Pi=Pf
3mv02i^=mv02i^+m3v02j^+mv
v =4 v 0 2 i ^ 3 v 0 2 j ^
v=5v02 

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