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Question: Answered & Verified by Expert
A projectile is fired with velocity v0 at an angle 60° with horizontal. At top of its trajectory, it explodes into three fragment of equal masses. First fragment retraces the path and the second moves vertically upward with speed 3v02 . The speed of third fragment is
PhysicsCenter of Mass Momentum and CollisionNEET
Options:
  • A 3v02
  • B 5v02
  • C v0
  • D 2v0
Solution:
1375 Upvotes Verified Answer
The correct answer is: 5v02


Let velocity of the third fragment be v

Pi=Pf

3m.v02i^=-mv02i^+m.3v02j^+mv

v=4v02i^-3v02j^

v=5v02

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