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Question: Answered & Verified by Expert
A projectile is given an initial velocity of \( \hat{i}+2 \hat{j} \). The Cartesian equation of its path is: \( \left(g=10 m / s^{2}\right) \)
(Here, \( \hat{i} \) is unit vector along horizontal and \( \hat{j} \) is unit vector vertically upwards)
PhysicsMotion In Two DimensionsJEE Main
Options:
  • A \( y=2 x-5 x^{2} \)
  • B \( y=x-5 x^{2} \)
  • C \( 4 y=2 x-5 x^{2} \)
  • D \( y=2 x-25 x^{2} \)
Solution:
1444 Upvotes Verified Answer
The correct answer is: \( y=2 x-5 x^{2} \)

tanθ=usinθucosθ=21

The desired equation is :

y=xtanθ-gx22u2cos2θ

or   y=x2-10 x22 22+122 152

or    y=2x-5x2

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