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Question: Answered & Verified by Expert
A projectile is given an initial velocity of i^+2j^ m s-1. The Cartesian equation of its path is g=10 m s-1 (Here, i^ is the unit vector along horizontal and j^ is unit vector vertically upwards)
PhysicsMotion In Two DimensionsNEET
Options:
  • A y=2x-5x2
  • B y=x-5x2
  • C 4y=2x-5x2
  • D y=2x-25x2
Solution:
1720 Upvotes Verified Answer
The correct answer is: y=2x-5x2
tanθ=usinθucosθ=21



The desired equation is :

y=xtanθ-gx22u2cos2θ

y=x2-10x22(22+12)2152

y=2x-5x2.

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