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Question: Answered & Verified by Expert
A projectile is given an initial velocity of i^+2j^. What is the Cartesian equation of its path? g =  10 m s-(Here,i^  is the unit vector along horizontal and j^ is unit vector vertically upwards)
PhysicsMotion In Two DimensionsNEET
Options:
  • A y=2x-5x2
  • B y=x-5x2
  • C 4y=2x-5x2
  • D y=2x-25x2
Solution:
1225 Upvotes Verified Answer
The correct answer is: y=2x-5x2
tanθ=u sinθucosθ=21




The desired equation is:

y=xtanθ-gx22u2cos2θ

Or y=x2-10x2222+122152

Or y=2x-5x2

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