A projectile with speed 50 m s - 1 is thrown at an angle of 60 ° with the horizontal. The maximum height that can be reached is, (acceleration due to gravity = 10 m s - 2 )

Question

A projectile with speed 50 m s - 1 is thrown at an angle of 60 ° with the horizontal. The maximum height that can be reached is, (acceleration due to gravity = 10 m s - 2 ), 90 . 75 m, 70 . 00 m, 85 . 00 m, 93 . 75 m

MARKS App · Accepted Answer

Maximum height of the projectile is given by, H = u 2 sin θ 2 2 g . Given: u = 50 m s - 1 & θ = 60 ° . H = 50 2 sin 60 ° 2 2 × 10 = 2500 × 3 2 2 20 = 93 . 75 m

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