A proton and an antiproton come close to each other in vacuum such that the distance between them is 10 cm . Consider the potential energy to be zero at infinity. The velocity at this distance will be:

Question

A proton and an antiproton come close to each other in vacuum such that the distance between them is 10 cm . Consider the potential energy to be zero at infinity. The velocity at this distance will be:, 1 . 17 m / s, 2 . 3 m / s, 3 . 0 m / s, 23 m / s

MARKS App · Accepted Answer

Applying mechanical energy conservation K i + U i = K f + U f 0 + 0 = 1 2 m v 2 + 1 2 m v 2 + k q 1 q 2 r q 1 = q 2 = e , q 1 = + e q 2 = - e and r = 0 . 1 m ∴ m v 2 = k e 2 r ∴ v 2 = k e 2 m r = 9 × 10 9 × 1 . 6 × 10 - 19 2 1 . 67 × 10 - 27 ( 0 . 1 ) v ≃ 1 . 17 m / s

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