Search any question & find its solution
Question:
Answered & Verified by Expert
A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of $1 \mathrm{kV}$, its kinetic energy will be
Options:
Solution:
1754 Upvotes
Verified Answer
The correct answer is:
$1 \mathrm{keV}$
The charge on a proton is equal to $e$, the electronic charge. The potential difference is $V=1 \mathrm{kV}$. Hence the kinetic energy of the proton is $E=1 \mathrm{keV}$.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.