A proton is moving perpendicular to a uniform magnetic field of 2 . 5 T with 2 MeV kinetic energy. The force on proton (in N ) is (Mass of proton = 1.6 × 10 - 27 kg ,Charge of the proton = 1.6 × 10 - 19 C )

Question

A proton is moving perpendicular to a uniform magnetic field of 2 . 5 T with 2 MeV kinetic energy. The force on proton (in N ) is (Mass of proton = 1.6 × 10 - 27 kg ,Charge of the proton = 1.6 × 10 - 19 C ), 8 × 10 - 12, 8 × 10 - 11, 3 × 10 - 11, 3 × 10 - 10

MARKS App · Accepted Answer

Force on moving charge in magnetic field F = q v B sin ⁡ θ But θ = 90 F = q v B Hence velocity v = 2 E m ( E is the kinetic energy of proton) Putting the values we get F = 8 × 10 - 12 N

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