A proton moving with a velocity of 1.25 × 10 5 m s - 1 collides with a stationary helium atom. The velocity of the proton after the collision is

Question

A proton moving with a velocity of 1.25 × 10 5 m s - 1 collides with a stationary helium atom. The velocity of the proton after the collision is, 0.75 × 10 5 m s - 1, 7.5 × 10 5 m s - 1, - 0.75 × 10 5 m s - 1, 0 m s - 1

MARKS App · Accepted Answer

From momentum conservation m p u 1 = m p v 1 + m He v 2 ⇒ u 1 = v 1 + 4 v 2 ...(i) For elastic collision e = 1 e = v 2 − v 1 u 1 ⇒ u 1 = v 2 − v 1 ...(ii) From equation (i) and equation (ii), we get v 2 = 2 5 u 1 and v 1 = − 3 5 u 1 ∴ v 1 = − 3 5 × 1.25 × 10 5 m s - 1 = − 0.75 × 10 5 m s − 1

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