A proton of mass m and charge + e is moving in a circular orbit in a magnetic field with energy 1 MeV . What should be the energy of α - p a r t i c l e ( m a s s = 4 m and c h a r g e = + 2 e ), so that it can revolve in the path of the same radius?

Question

A proton of mass m and charge + e is moving in a circular orbit in a magnetic field with energy 1 MeV . What should be the energy of α - p a r t i c l e ( m a s s = 4 m and c h a r g e = + 2 e ), so that it can revolve in the path of the same radius?, 1 MeV, 4 MeV, 2 MeV, 0.5 MeV

MARKS App · Accepted Answer

r = 2 m K q B ⇒ K ∝ q 2 m ⇒ K p K α = q p q α 2 × m α m p ⇒ 1 K α = q p 2 q p 2 × 4 m p m p = 1 ⇒ K α = 1 MeV .

Search any question & find its solution

Looking for more such questions to practice?