A proton, when accelerated through a potential difference of V = 29 . 6 V , has a wavelength λ associated with it. An α - particle, in order to have the same λ , must be accelerated through a potential difference of how many volts?

Question

A proton, when accelerated through a potential difference of V = 29 . 6 V , has a wavelength λ associated with it. An α - particle, in order to have the same λ , must be accelerated through a potential difference of how many volts?,

MARKS App · Accepted Answer

λ P = λ α o r h 2 m p Q P V p = h 2 m α Q α V α ∴ m p Q p V p = m α Q α V α ∴ V α = m p m α Q p Q α V p ⇒ V α = 1 4 1 2 × 29 . 6 V = 3 . 7 V

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