A radiation of energy E falls normally on a perfectly reflecting surface. The momentum transferred to the surface is ( C = Velocity of light)

Question

A radiation of energy E falls normally on a perfectly reflecting surface. The momentum transferred to the surface is ( C = Velocity of light), E C, 2 E C, 2 E C 2, E C 2

MARKS App · Accepted Answer

E = h C λ P = h λ ⇒ P = E C Initial momentum of light when falls on a perfectly reflecting surface. P i = E C When it is reflected momentum is in opposite direction P f = - E C Net momentum = P f - P i = - E C - E C = - 2 E C Δ P = 2 E C

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