A radioactive nucleus A Z X undergoes spontaneous decay in the sequence A Z X → Z - 1 B → Z - 3 C → Z - 2 D , where Z is the atomic number of element X . The possible decay particles in the sequence are:

Question

A radioactive nucleus A Z X undergoes spontaneous decay in the sequence A Z X → Z - 1 B → Z - 3 C → Z - 2 D , where Z is the atomic number of element X . The possible decay particles in the sequence are:, α , β - , β +, α , β + , β -, β + , α , β -, β - , α , β +

MARKS App · Accepted Answer

As we know due to α -decay atomic number decreases by 2 and mass no. decreases by 4 . And due to β - decay mass no. remain unchanged and atomic no. increases by 1 And due to β + decay mass no. remain unchanged but atomic no. decreases by 1 . So, option ( 3 ) is correct option.

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