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Question: Answered & Verified by Expert
A radioactive nucleus has specific binding energy $\mathrm{E}_{1}$. It emits an $\alpha$-particle. The resulting nucleus has specific binding energy $\mathrm{E}_{2}$. Then
PhysicsNuclear PhysicsKCETKCET 2012
Options:
  • A $\mathrm{E}_{2}=0$
  • B $\mathrm{E}_{2}=\mathrm{E}_{1}$
  • C $\mathrm{E}_{2} < \mathrm{E}_{1}$
  • D $\mathrm{E}_{2}>\mathrm{E}_{1}$
Solution:
2361 Upvotes Verified Answer
The correct answer is: $\mathrm{E}_{2}>\mathrm{E}_{1}$
The nucleus become more stable on emission of $\alpha$-particle, hence $\mathrm{E}_{2}>\mathrm{E}_{1}$.

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