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A radioactive substance emits 100 beta particles in the first $2 \mathrm{~s}$ and 50 beta particles in the next $2 \mathrm{~s}$. The mean life of the sample is
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Verified Answer
The correct answer is:
$\frac{2}{0.693} \mathrm{~s}$
Given, In 1st two seconds $100 \beta$ particles and in next two seconds $50 \beta$ particles are emitted
$\begin{array}{ll}
\therefore & T_{1 / 2}=2 \mathrm{~s} \\
\text { Hence, } & T_{m}=\frac{T_{1 / 2}}{0.693}=\frac{2}{0.693}
\end{array}$
$\begin{array}{ll}
\therefore & T_{1 / 2}=2 \mathrm{~s} \\
\text { Hence, } & T_{m}=\frac{T_{1 / 2}}{0.693}=\frac{2}{0.693}
\end{array}$
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