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A random variable $X$ has the following probability distribution :
Find the (c)(d)f. of $X$
Options:
Find the (c)(d)f. of $X$
- A
- B
- C
- D
Solution:
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Verified Answer
The correct answer is:
$F(x)=P(X < x)$
$\begin{aligned}
&F(0)=P(X \leq 0)=0.5 \\
&F(1)=P(X \leq 1)=0.5+0.2=0.7 \\
&F(2)=P(X \leq 2)=0.5+0.2+0.18=0.88 \\
&F(3)=P(X \leq 3)=0.5+0.2+0.18+0.12=1
\end{aligned}$
$\therefore$ The c.d.f. of $X$ is
$\begin{aligned}
&F(0)=P(X \leq 0)=0.5 \\
&F(1)=P(X \leq 1)=0.5+0.2=0.7 \\
&F(2)=P(X \leq 2)=0.5+0.2+0.18=0.88 \\
&F(3)=P(X \leq 3)=0.5+0.2+0.18+0.12=1
\end{aligned}$
$\therefore$ The c.d.f. of $X$ is
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