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A ray of light incident at an angle $\theta$ on a refracting face of a prism emerges from the other face normally. If the angle of the prism is $5^{\circ}$ and the prism is made of a material of refractive index $1.5$, the angle of incidence is
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The correct answer is:
$7.5^{\circ}$
$7.5^{\circ}$
As we know that the deviation
$$
\delta=(\mu-1) \mathrm{A}
$$
By geometry, the angle of refraction by first surface is $5^{\circ}$ and given $\mu=1.5$
So, $\quad \delta=(1.5-1) \times 5^{\circ}=2.5^{\circ}$ also, $\quad \delta=\theta-\mathrm{r}, \quad$.... (ii) By putting the value of $\delta$ and $r$ in equation (ii)
$$
\delta=(\mu-1) \mathrm{A}
$$
By geometry, the angle of refraction by first surface is $5^{\circ}$ and given $\mu=1.5$
So, $\quad \delta=(1.5-1) \times 5^{\circ}=2.5^{\circ}$ also, $\quad \delta=\theta-\mathrm{r}, \quad$.... (ii) By putting the value of $\delta$ and $r$ in equation (ii)
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