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A ray of light incident on a transparent sphere at an angle $\pi / 4$ and refracted at an angle $r$, emerges from the sphere after suffering one internal reflection. The total angle of deviation of the ray is
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The correct answer is:
$\frac{3 \pi}{2}-4 r$

$\mathrm{S}_{1}=\frac{\pi}{4}-\mathrm{r}$
$\mathrm{S}_{2}=\pi-2 \mathrm{r}$
$\mathrm{S}_{3}=\frac{\pi}{4}-\mathrm{r}$
$\mathrm{S}=\mathrm{S}_{1}+\mathrm{S}_{2}+\mathrm{S}_{3}=\frac{3 \pi}{2}-4 \mathrm{r}$
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