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A ray of light is incident at the glass-water interface at an angle i, it emerges finally parallel to the surface of water, then the value of $\mu_{\mathrm{g}}$ would be
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The correct answer is:
$1 / \sin i$
$\mu_{g} \sin i=\mu_{\text {air }} \sin 90^{\circ} \Rightarrow \mu_{g}=\frac{1}{\sin i}$
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