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A ray of light is incident on a $60^{\circ}$ prism at the minimum deviation position. The angle of refraction at the first face (ie, incident face) of the prism is
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Verified Answer
The correct answer is:
$30^{\circ}$
The refracting angle of prism
$A=r_1+\mathrm{r}_2$
For minimum deviation
$\begin{array}{l}
\mathrm{r}_1 =\mathrm{r}_2=\mathrm{r} \\
\therefore \mathrm{A} =2 \mathrm{r} \\
\text {or } \mathrm{r} =\frac{\mathrm{A}}{2}=\frac{60^{\circ}}{2}=30^{\circ}
\end{array}$
$A=r_1+\mathrm{r}_2$
For minimum deviation
$\begin{array}{l}
\mathrm{r}_1 =\mathrm{r}_2=\mathrm{r} \\
\therefore \mathrm{A} =2 \mathrm{r} \\
\text {or } \mathrm{r} =\frac{\mathrm{A}}{2}=\frac{60^{\circ}}{2}=30^{\circ}
\end{array}$
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