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A ray of light is incident on a plane mirror at an angle of $60^{\circ}$. The angle of deviation produced by the mirror is
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Verified Answer
The correct answer is:
$60^{\circ}$
Here, angle of incidence, $i=60^{\circ}$
$\therefore$ Angle of deviation
$\begin{aligned} \delta &=180^{\circ}-(i+r) \\ &=180^{\circ}-2 i \\ &=180^{\circ}-2 \times 60^{\circ}=60^{\circ} \end{aligned} \quad($ As $i=r)$
$\therefore$ Angle of deviation
$\begin{aligned} \delta &=180^{\circ}-(i+r) \\ &=180^{\circ}-2 i \\ &=180^{\circ}-2 \times 60^{\circ}=60^{\circ} \end{aligned} \quad($ As $i=r)$
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