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A ray of light passes through an equilateral prism such that the angle of incidence (i) is equal to angle of emergence (e). The angle of emergence is equal to $\left(\frac{3}{4}\right)^{\text {th }}$ the angle of prism. The angle of deviation is
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$30^{\circ}$
$\therefore \quad \mathrm{i}=\mathrm{e}=60^{\circ} \times \frac{3}{4}=45^{\circ} \quad \ldots(\because$ prism is equilateral $)$
Angle of Deviation: $\delta=\mathrm{i}+\mathrm{e}-\mathrm{A}$ $\delta=45^{\circ}+45^{\circ}-60^{\circ}=30^{\circ}$
Angle of Deviation: $\delta=\mathrm{i}+\mathrm{e}-\mathrm{A}$ $\delta=45^{\circ}+45^{\circ}-60^{\circ}=30^{\circ}$
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