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A ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence and each one is equal to $3 / 4$ th the angle of prism. The angle of deviation is
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The correct answer is:
$30^{\circ}$
Relation among the $(i),(e),(A)$ and $(\delta)$
$i+e=A+\delta$
$\frac{3}{4} \times 60^{\circ}+\frac{3}{4} \times 60^{\circ}=60^{\circ}+\delta$
or $\quad 45^{\circ}+45^{\circ}=60^{\circ}+\delta$
or $\delta=30^{\circ}$
where, $i=$ angle of incidence
$e =\text { angle of emergence }$
$A =\text { angle of prism }$
$\delta =\text { angle of deviation }$
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