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A ray of light passing from glass to water is incident on the glass-water interface at $65^{\circ}$. If the critical angle for the pair of media is $63^{\circ}$.
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Verified Answer
The correct answer is:
The ray will be totally internally reflected back into glass with a deviation of $50^{\circ}$
Given, $i=65^{\circ}$ and $i_{c}=63^{\circ}$
Since, $i>i_{c}$, so the ray undergo total internal reflection.
The angle of deviation, $d=\pi-2 i$
$$
=180^{\circ}-2\left(65^{\circ}\right)=180^{\circ}-130^{\circ}=50^{\circ}
$$
Since, $i>i_{c}$, so the ray undergo total internal reflection.
The angle of deviation, $d=\pi-2 i$
$$
=180^{\circ}-2\left(65^{\circ}\right)=180^{\circ}-130^{\circ}=50^{\circ}
$$
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