A ray of sunlight enters a spherical water droplet ( n = 4 3 ) at an angle of incidence 53 ° measured with respect to the normal to the surface. It is reflected from the back surface of the droplet and re-enters into the air. The angle between the incoming and outgoing ray is [Take sin 53 ° = 0 . 8 ]

Question

A ray of sunlight enters a spherical water droplet ( n = 4 3 ) at an angle of incidence 53 ° measured with respect to the normal to the surface. It is reflected from the back surface of the droplet and re-enters into the air. The angle between the incoming and outgoing ray is [Take sin 53 ° = 0 . 8 ], 15 °, 34 °, 138 °, 30 °

MARKS App · Accepted Answer

Applying law of refraction ⇒ 1 × sin 5 3 ° = 4 3 × sin r 4 5 = 4 3 sin r ⇒ sin r = 3 5 ⇒ sin r = 0 . 6 ⇒ r = 3 7 ° δ 1 = 5 3 ° - 3 7 ° ⇒ δ 1 = 1 6 ° C.W. δ 2 = 1 8 0 - 2 × 3 7 ° ⇒ δ 2 = 1 0 6 ° C.W. δ 3 = 5 3° - 3 7 ° ⇒ δ 3 = 1 6 ° C.W. δ net = δ 1 + δ 2 + δ 3 = 1 3 8 °

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