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Question: Answered & Verified by Expert
A reaction is $A+B \rightarrow C+D$. Initially we start with equal concentration of $A$ and $B$. At equilibrium we find the moles of $C$ is two times of $A$. What is the equilibrium constant of the reaction.
ChemistryChemical EquilibriumJEE Main
Options:
  • A 4
  • B 2
  • C $1 / 4$
  • D $1 / 2$
Solution:
2752 Upvotes Verified Answer
The correct answer is: 4
$A+B \rightleftharpoons C+D$
at equilibrium $a a \quad 2 \alpha 2 a$
$K=\frac{2 a \times 2 a}{a \times a}=4$

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