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A rectangle \(A B C D\) has its side parallel to the line \(y=2 x\) and vertices \(A, B, D\) are on lines \(y=1, x=1\) and \(x=-1\) respectively. The coordinate of \(C\) can be
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Options:
  • A \((3,8)\)
  • B \((-3,8)\)
  • C \((-3,-1)\)
  • D None of these
Solution:
1161 Upvotes Verified Answer
The correct answers are: None of these
Hint: Case I


line \(y=2 x\ldots(1)\)
\(A D\) parallel to \(y=2 x\)
\(\Rightarrow \mathrm{M}_{\mathrm{AD}}=2 ~\&~ \mathrm{M}_{\mathrm{AB}}=-\frac{1}{2}\)
for \(a=3\)
\(A(3,1), B(1,2), C(-3,-6), D(-1,-7)\)

\(\begin{aligned} & \text { for } a=-3 \\ & C(3,3), A(-3,1), B(1,-1), D(-1,5)\end{aligned}\)

Case II AD perpendicular to line (1)
\(\Rightarrow M_{A D}=\frac{1}{2}, M_{A B}=2 \Rightarrow b=3-2 a \Rightarrow d=\frac{a+1}{2}\)

for \(a=3, C(-3,-2)\)

for \(a=-3, C(3,7)\)

\({ }^*\) In both cases if abscissa of \(C: 3\) or -3
then co-ordinates of \(C\) can be \((3,3)\) or \((3,7)\) or \((-3,-6)\) or \((-3,-2)\)

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