A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire is suspended vertically in a uniform magnetic field of strength 0.2 W e b e r / m 2 . The coil carries a current of 2 A . If the plane of the coil is inclined at an angle of 30 o with the direction of the field, the torque required to keep coil in stable equilibrium will be:

Question

A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire is suspended vertically in a uniform magnetic field of strength 0.2 W e b e r / m 2 . The coil carries a current of 2 A . If the plane of the coil is inclined at an angle of 30 o with the direction of the field, the torque required to keep coil in stable equilibrium will be:, 0.20 N m, 0.24 N m, 0.12 N m, 0.15 N m

MARKS App · Accepted Answer

τ → = M → × B → = M B sin ⁡ 60 o = N i A B sin ⁡ 60 o = 50 × 2 × 0.12 × 0.1 × 0.2 × 3 2 = 12 3 × 10 - 2 N m = 0.20748 N m

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