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Question: Answered & Verified by Expert

A rectangular glass slab ABCD, of refractive index,   n 1 ,  is immersed in water of refractive index   n 2 ( n 1 > n 2 ).  A ray of light is incident at the surface AB of the slab, as shown. The maximum value of the angle of incidence   α max , such that the ray comes out only from the other surface CD, is given by


 

PhysicsRay OpticsJEE Main
Options:
  • A

     sin1[n1n2cos(sin1n2n1)]

  • B

     sin1[n1cos(sin11n2)]

  • C

     sin1(n1n2)

  • D

     sin1(n2n1)

Solution:
2844 Upvotes Verified Answer
The correct answer is:

 sin1[n1n2cos(sin1n2n1)]

Consider the figure. The ray will come out from CD if it suffers a total internal reflection at surface AD, i.e., it strikes the surface AD at critical angle C (the limiting case).

Applying Snell’s law at P, we get

  n 1 sinC= n 2 orsinC= n 2 n 1

Applying snell’s law at Q, we get

  n 2 sinα= n 1 cosC;

  sinα= n 1 n 2 cos{ sin 1 ( n 2 n 1 ) }

or    α= sin 1 [ n 1 n 2 cos{ sin 1 ( n 2 n 1 ) } ]

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