Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A rectangular loop of length 2.5 m and width 2 m is placed at 60° to a magnetic field of 4 T. The loop is removed from the field in 10 sec. The average emf induced in the loop during this time is
PhysicsElectromagnetic InductionJEE MainJEE Main 2024 (27 Jan Shift 1)
Options:
  • A -2 V
  • B +2 V
  • C +1 V
  • D -1 V
Solution:
1100 Upvotes Verified Answer
The correct answer is: +1 V

The formula to calculate the change in the magnetic flux associated with the given loop can be written as

ϕ=-BAcosθ=-Blbcosθ   ...1

The formula to calculate the induced emf is given by

ε=-ϕt=Blbcosθt   ...2

From equation (2), it follows that

ε=4×2.5×2×cos60°10 V=1 V

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.