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Question: Answered & Verified by Expert
A rectangular loop of metallic wire is of length a and breadth b and carries a current i. The magnetic field at the centre of the loop is
PhysicsMagnetic Effects of CurrentNEET
Options:
  • A μ0i4π8a2+b2ab
  • B μ0i4π4a2+b2ab
  • C μ0i4π2a2+b2ab
  • D μ0i4πa2+b2ab
Solution:
2956 Upvotes Verified Answer
The correct answer is: μ0i4π8a2+b2ab
From figure it is clear that



BAB=BCD

=μ0i4πb2sinϕ1+sinϕ2=μ04π4ibaa2+b2

BBC=BDA=μ04π4iaba2+b2

B=BAB+BBC+BCD+BDA

B=2μ04π4ibaa2+b2+2μ04π4iaba2+b2

B=μ04π2×4ia2+b2ab+ba

B=μ04π8ia2+b2ab

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