A rectangular solid box of length 0.3 m is held horizontally, with one of its sides on the edge of a platform of height 5 m . When released, it slips off the table in a very short time τ = 0.01 s , remaining essentially horizontal. The angle by which it would rotate when it hits the ground will be (in radians) close to:

Question

A rectangular solid box of length 0.3 m is held horizontally, with one of its sides on the edge of a platform of height 5 m . When released, it slips off the table in a very short time τ = 0.01 s , remaining essentially horizontal. The angle by which it would rotate when it hits the ground will be (in radians) close to:, 0.5, 0.3, 0.02, 0.28

MARKS App · Accepted Answer

Angular impulse = change in angular momentum τ Δ t = Δ L m g l 2 × 0.01 = m l 2 3 ω ω = 3 g × 0.01 2 l = 3 × 10 × 0.01 2 × 0.3 = 0.5 r a d / s e c Time taken by rod to hit the ground = 2 h g = 2 × 5 10 = 1 s Angle rotated by rod = ω t = 0.5 × 1 = 0.5 r a d

Search any question & find its solution

Looking for more such questions to practice?